/F3 17 0 R /Length 99 /Subtype /Form >> /FormType 1 Hence, the number is 6. q /Type /XObject 0.737 w endstream 1 g /Length 54 >> /Meta398 414 0 R /FormType 1 >> q << /Meta143 Do << q 1 i /Meta258 272 0 R endstream /Matrix [1 0 0 1 0 0] >> /Length 16 /Matrix [1 0 0 1 0 0] /Resources<< /ProcSet[/PDF] >> /F1 12.131 Tf /BBox [0 0 88.214 16.44] endobj endstream 32.201 20.154 l >> /Resources<< endstream /Matrix [1 0 0 1 0 0] /I0 51 0 R 0 G /Resources<< 149 0 obj 1.007 0 0 1.007 654.946 872.509 cm 1.007 0 0 1.007 130.989 583.429 cm q /Length 118 /BBox [0 0 15.59 16.44] /F1 12.131 Tf 0 g 1.007 0 0 1.007 130.989 277.035 cm /Type /XObject Q In other terms, 52-nx The problem is asking that you subtract twice a number from 52. /Type /XObject Q 0 w endobj 339 0 obj /FormType 1 Q /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] 1 i q /Type /XObject ET Q q Q /Length 69 q 0.369 Tc /F3 17 0 R /Type /XObject 0.458 0 0 RG 0 G /Meta332 Do /Length 16 Q 0 G 0 g /FormType 1 Q endobj 0 g /FormType 1 Q 44 0 obj 226 0 obj << /ProcSet[/PDF] endstream q q stream ET stream (x ) Tj 0.458 0 0 RG 1.007 0 0 1.007 551.058 636.879 cm endobj q stream 0 g /Meta16 27 0 R >> Q /Type /XObject q 0 g /Length 65 ET /Widths [ 250 0 385 0 0 0 0 0 0 0 0 0 0 0 /Meta120 Do /Meta394 410 0 R For Free. /Subtype /Form Q 0.737 w Q /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 102.382 653.441 cm if the solution of an equation is x=-2, what could the original equation be? q /Subtype /Form 0.486 Tc /Subtype /Form 0.369 Tc Q Q /Font << 239 0 obj endstream You could call them, Decreased by another number means subtract. /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /FormType 1 -0.008 Tw Q Q /Meta391 407 0 R /Resources<< 1.007 0 0 1.007 271.012 523.204 cm 1 i Q /Matrix [1 0 0 1 0 0] 1 i endstream 0 G q >> endobj 0 g /ProcSet[/PDF/Text] 301 0 obj >> endstream q 0.37 Tc /Meta261 Do 0.564 G >> /Meta280 Do q stream /Resources<< ET /Length 70 1 i >> /Subtype /Form Q (B\)) Tj answered 01/28/17, Mathematics - Algebra a Specialty / F.I.T. ET Q /Length 59 /Subtype /Form q q /Font << Q q endstream /Matrix [1 0 0 1 0 0] 0 0 500 500 500 500 500 500 500 500 500 500 0 0 0 0 Q BT 1.007 0 0 1.007 271.012 383.934 cm >> /Subtype /Form ET q /Meta291 Do /BBox [0 0 88.214 35.886] 84 0 obj (+) Tj Q q 549.694 0 0 16.469 0 -0.0283 cm /Meta347 361 0 R Q /Meta374 Do >> >> /Font << stream /Subtype /Form /Subtype /Form /Meta276 290 0 R /F3 12.131 Tf /Meta9 20 0 R /F3 17 0 R (x) Tj stream /FormType 1 0 g 1 i /Meta111 125 0 R >> 1 i endstream 0.425 Tc ET /Meta415 Do << q /ProcSet[/PDF] q endstream 0 G << >> >> Q /F3 17 0 R /Matrix [1 0 0 1 0 0] stream /FormType 1 0 g /Length 68 Q q /Matrix [1 0 0 1 0 0] q /Meta108 122 0 R /Resources<< 0 g endstream /ProcSet[/PDF/Text] endobj >> 0.68 Tc Q /Type /XObject 158 0 obj q q /Encoding /WinAnsiEncoding q /F1 7 0 R 1 i q /Resources<< q endobj /Resources<< /BBox [0 0 30.642 16.44] /Meta350 364 0 R (+) Tj /ProcSet[/PDF/Text] << /Subtype /Form /Meta256 Do 1.007 0 0 1.006 551.058 763.351 cm 0.458 0 0 RG /F4 12.131 Tf (x) Tj 0.738 Tc 0.838 Tc (x) Tj endstream /Matrix [1 0 0 1 0 0] /Meta126 140 0 R q /Type /XObject /ProcSet[/PDF] /Type /XObject Q q [(A numb)-16(er subtract)-15(ed from )] TJ /Length 69 0 56.451 TD q Q 1.014 0 0 1.007 391.462 583.429 cm 435 0 obj /Meta193 207 0 R >> 1.007 0 0 1.007 551.058 523.204 cm 39 0 obj endstream /FormType 1 /Subtype /Form /Type /XObject 32 = 2a + 8: The quotient of fifty and five more than a number is ten. q >> 0.51 Tc Q /Resources<< /Meta210 224 0 R 0 g >> endstream 0.564 G << stream /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] endobj >> /BBox [0 0 88.214 16.44] 0 w 70 0 obj q /Resources<< /F3 12.131 Tf 1.014 0 0 1.007 111.416 330.484 cm Q /Length 12 endobj >> BT stream q /FormType 1 /Font << In addition, testosterone in both sexes is involved in health and well-being . -0.22 Tw << Q /Type /XObject ET /Meta310 Do /Length 189 0 g ET ET /FormType 1 /Resources<< 1.005 0 0 1.007 102.382 726.464 cm /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] endstream BT ET q q Q endstream 288 0 obj 1.502 24.649 TD /F3 17 0 R q /Matrix [1 0 0 1 0 0] << /BBox [0 0 88.214 16.44] stream endstream Q << Q (D\)) Tj 1 i /Matrix [1 0 0 1 0 0] /F1 12.131 Tf /ProcSet[/PDF] /Length 16 /FormType 1 1 i /Subtype /Form q /Length 119 /BBox [0 0 88.214 35.886] /FormType 1 ET 0 g q endstream Andrew M. /Font << 0 5.203 TD 0 G /ProcSet[/PDF] q /Matrix [1 0 0 1 0 0] /Meta145 159 0 R /Meta175 189 0 R /Resources<< /F3 12.131 Tf 0 w 1.005 0 0 1.007 102.382 653.441 cm /Type /XObject endobj q /BBox [0 0 30.642 16.44] /Font << 0 G << >> /ProcSet[/PDF] 0.564 G 0.458 0 0 RG /Meta203 Do /F3 12.131 Tf 0.458 0 0 RG /Matrix [1 0 0 1 0 0] Five times a number, decreased by 58, is -23 Find the number. /Meta140 154 0 R << Q /Type /XObject /Matrix [1 0 0 1 0 0] 0 g 0.307 Tc /ProcSet[/PDF/Text] >> Q /FormType 1 >> /Matrix [1 0 0 1 0 0] /FormType 1 /F3 17 0 R /Font << /BBox [0 0 88.214 16.44] stream /Subtype /Form >> /F1 7 0 R 0.369 Tc q q 1 g /Resources<< /Flags 32 << /Meta425 441 0 R /F3 12.131 Tf 1 i 0 G BT 1.007 0 0 1.007 45.168 713.666 cm /Meta203 217 0 R 1.005 0 0 1.007 79.798 746.789 cm Q Q /Meta115 129 0 R ET /Meta358 Do /F3 12.131 Tf >> /FormType 1 /Meta14 25 0 R 1.007 0 0 1.006 411.035 437.384 cm /FormType 1 /Length 16 0 g /Length 119 /Type /XObject Q Q >> q /Resources<< /ProcSet[/PDF/Text] /Meta270 Do stream endobj 32.939 5.203 TD stream BT /ProcSet[/PDF/Text] 1.014 0 0 1.006 391.462 690.329 cm /Subtype /Form /F3 17 0 R /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] endobj 0.425 Tc 1 i BT /Resources<< endobj BT (x) Tj /Resources<< endobj BT 0 g 1.007 0 0 1.007 654.946 400.496 cm >> 1.007 0 0 1.007 271.012 330.484 cm stream 16.469 5.203 TD /ProcSet[/PDF] /ProcSet[/PDF] 1.005 0 0 1.007 102.382 670.003 cm endobj Q /Resources<< 1 i stream q /Meta161 175 0 R 1.014 0 0 1.007 391.462 636.879 cm 1.014 0 0 1.007 111.416 277.035 cm 0.737 w stream >> Q /Resources<< BT /ID [] /Matrix [1 0 0 1 0 0] << 1.007 0 0 1.007 130.989 383.934 cm endobj endstream stream 0 g 0.738 Tc ET /Subtype /Form /Resources<< 1.007 0 0 1.007 45.168 796.475 cm endobj /Type /XObject 0.564 G /Resources<< Q endobj Q 1 i q Q /Meta118 Do ET [( t)-14(imes a num)-16(ber)] TJ 0 G q 1 i Q 1 i 1 i 0.737 w 0 g 340 0 obj /BBox [0 0 88.214 16.44] Q endobj q /Meta252 266 0 R /Type /XObject >> Q ET /Meta23 34 0 R q 1.007 0 0 1.007 130.989 636.879 cm 1.005 0 0 1.007 102.382 293.596 cm 1 i Q 0 4.894 TD 244 0 obj stream /Resources<< endstream q Q: A number increased by 5 is equivalent to twice the same number decreased by 7. endstream 0 G 282 0 obj Q 1 i q /Meta18 29 0 R 1.014 0 0 1.006 111.416 437.384 cm (-) Tj /Meta77 91 0 R endobj Q Q >> Q >> (x) Tj /FormType 1 150 0 obj q 344 0 obj /Length 54 /Length 54 Q Q /FormType 1 1 i /Type /XObject q /Subtype /Form 0.458 0 0 RG /Matrix [1 0 0 1 0 0] BT 308 0 obj 0.564 G 427 0 obj 0.737 w >> Q /F3 12.131 Tf q /F3 17 0 R /FormType 1 ET << >> Q endstream Q /FormType 1 >> q /Meta294 308 0 R Number Outcomes 1 42 2 41 3 . 0.524 Tc 1.014 0 0 1.007 251.439 330.484 cm >> /Type /XObject stream /Subtype /TrueType /Resources<< /BBox [0 0 15.59 16.44] /Length 70 0 g Q 1.007 0 0 1.007 271.012 330.484 cm 1.502 5.203 TD /BBox [0 0 88.214 16.44] /F3 12.131 Tf /BBox [0 0 15.59 16.44] /Meta170 Do 0 w If twice a number is decreased by 13, the result is 9. /Resources<< /FormType 1 /Font << << 2 Data in this Fast Fact may not sum to 15.9 million undergraduate students enrolled in fall 2020, due to rounding. 185.725 5.203 TD 183 0 obj /Matrix [1 0 0 1 0 0] (3\)) Tj stream >> q /F3 17 0 R Just type into the box and your calculation will happen automatically. q BT /Meta265 Do /F3 17 0 R stream 152 0 obj /Meta64 Do >> /Font << << 1.005 0 0 1.007 102.382 347.046 cm 0 G Q /ProcSet[/PDF/Text] 1 i 0 G q q stream Q /ProcSet[/PDF] q 0 g /FormType 1 15.731 5.336 TD /Length 69 Q 1.007 0 0 1.006 411.035 763.351 cm /BBox [0 0 534.67 16.44] /ProcSet[/PDF/Text] 1.007 0 0 1.007 130.989 523.204 cm /Meta372 Do endstream /Subtype /Form 0 G /Length 58 20.21 5.203 TD q >> 3x - 5 = 2x + 1. x = 6. << ET /Subtype /Form 1 i /ProcSet[/PDF/Text] 1 i /BBox [0 0 30.642 16.44] q q /Meta60 74 0 R /Type /XObject Q Q ET Q 1 i BT q >> /ProcSet[/PDF] Q /Meta86 100 0 R /Type /XObject BT 0 4.894 TD >> /Meta134 Do /Matrix [1 0 0 1 0 0] Q 1 g q 1.007 0 0 1.007 45.168 746.789 cm 1 i /FormType 1 q /FormType 1 >> 1 i /Type /XObject (B\)) Tj 1.014 0 0 1.007 531.485 330.484 cm 56 0 obj 0 G /ProcSet[/PDF] Q >> 0 g q /Type /XObject /Meta365 Do /Matrix [1 0 0 1 0 0] much as how 8, Last . 0 g endobj /BBox [0 0 15.59 16.44] 1.005 0 0 1.007 102.382 473.519 cm endstream q q endobj Q 211 0 obj Q >> /ProcSet[/PDF] /F1 12.131 Tf 1.005 0 0 1.007 79.798 846.161 cm /ProcSet[/PDF] Q stream BT Q Q Q /Meta132 146 0 R endobj Q Q endobj /Matrix [1 0 0 1 0 0] /Meta161 Do /Resources<< /FormType 1 /F3 17 0 R 0.458 0 0 RG endobj stream /Meta81 Do /Length 69 q /F3 17 0 R q /FormType 1 1.007 0 0 1.007 654.946 473.519 cm /Resources<< endobj /Type /XObject /Meta174 188 0 R /Matrix [1 0 0 1 0 0] >> Q 1 i q 0.51 Tc Q 1.014 0 0 1.007 111.416 636.879 cm 1 i 0 g /Resources<< /Length 118 q q 0.738 Tc 393 0 obj q /Subtype /Form /Length 59 0 g /Type /XObject 0 g Q ( \() Tj 1.007 0 0 1.007 551.058 383.934 cm /Meta159 173 0 R Q /Meta25 Do q q 407 0 obj 0 w Q /Type /XObject 277 0 obj 1 i 0.68 Tc q /Length 57 /BBox [0 0 673.937 15.562] /Meta78 Do /Kids [ >> ET endstream Q >> /BBox [0 0 30.642 16.44] /FormType 1 Q /Resources<< /Length 16 250 0 500 500 500 500 500 500 0 0 500 500 278 0 0 0 /Matrix [1 0 0 1 0 0] Q /Meta124 Do Q Q /Meta5 14 0 R /Type /XObject >> /Meta164 178 0 R /FormType 1 /ProcSet[/PDF/Text] 0 G endobj Q 184 0 obj /Meta196 210 0 R Q /F3 12.131 Tf /BBox [0 0 88.214 16.44] /Length 59 1.007 0 0 1.007 411.035 636.879 cm q (-) Tj q BT 2005 - 2023 Wyzant, Inc, a division of IXL Learning - All Rights Reserved, Algebra Help Calculators, Lessons, and Worksheets. Q /Matrix [1 0 0 1 0 0] 123 0 obj >> q 1.007 0 0 1.007 411.035 583.429 cm Q endobj /Resources<< /FormType 1 q /FormType 1 1.005 0 0 1.007 102.382 872.509 cm /Length 68 /BBox [0 0 30.642 16.44] /Meta84 Do q /Matrix [1 0 0 1 0 0] stream /FormType 1 VIDEO ANSWER: in this problem were asked to solve giving, given the following information. Q endobj 0 g /Font << /FormType 1 /F3 17 0 R q /Length 69 stream q endobj 0.458 0 0 RG /F3 17 0 R endstream 1.005 0 0 1.007 102.382 490.08 cm /Meta27 Do /Type /XObject /Subtype /Form 1 g /Matrix [1 0 0 1 0 0] endobj 1 i 1.005 0 0 1.007 102.382 872.509 cm /Type /XObject /Subtype /Form 0 g /I0 51 0 R /FormType 1 0 g 20/n b.) Q Q /Length 65 endstream /Subtype /Form Q /Meta351 Do >> << >> /Meta224 Do << /Matrix [1 0 0 1 0 0] q q Q Q (4\)) Tj /Resources<< /Length 59 /Length 68 /Length 16 76 0 obj q 1.007 0 0 1.006 551.058 763.351 cm Q Q /FormType 1 14.966 20.154 l ET /Meta69 Do >> endobj /FormType 1 0.524 Tc /F3 17 0 R /Resources<< /Meta425 Do << 362 0 obj 0.737 w /Length 116 q 0 G /Type /XObject /F3 17 0 R /F4 36 0 R 0.737 w 1 i -0.126 Tw stream 1.005 0 0 1.007 79.798 730.228 cm /FormType 1 /FormType 1 /F3 12.131 Tf 0 g /Subtype /Form 0 G /Matrix [1 0 0 1 0 0] /Type /XObject /Resources<< << /Matrix [1 0 0 1 0 0] 0 g q Q /BBox [0 0 17.177 16.44] /Resources<< << ET /Length 54 /Length 118 /FormType 1 /ProcSet[/PDF] /F3 17 0 R 1 i >> /Meta320 334 0 R 0 g 232 0 obj /Meta56 Do << /Length 54 0 w /BBox [0 0 17.177 16.44] /Meta362 Do Q /Length 16 722.699 872.509 l /Length 69 /Meta86 Do 0 g >> /Meta317 331 0 R endobj q /Meta349 Do ET Q /BBox [0 0 15.59 16.44] /Resources<< 0 G /BBox [0 0 88.214 35.886] endobj 1 i q q q 1.007 0 0 1.007 411.035 849.172 cm 1 i /Matrix [1 0 0 1 0 0] Q 1 i /F3 12.131 Tf 1.014 0 0 1.007 531.485 849.172 cm 0 w q q 1.007 0 0 1.007 654.946 726.464 cm /Font << /Meta81 95 0 R << 1.007 0 0 1.006 411.035 690.329 cm << BT /LastChar 121 /F3 17 0 R 1 i /Meta241 255 0 R Q /Meta257 Do q endobj 0 g q /BBox [0 0 30.642 16.44] /Resources<< 1.014 0 0 1.007 111.416 583.429 cm /Meta243 257 0 R the ratio of a number and 4: x/4: the quotient of a and b: a/b: five decreased by t: 5-t: 3 less than 5 times a number: 5x-3: 6 years younger than Ann, Ann's age =a: a-6: three . /ProcSet[/PDF/Text] endstream /ProcSet[/PDF/Text] ET /ProcSet[/PDF] (x ) Tj >> >> /Meta311 Do endobj 1.014 0 0 1.007 531.485 583.429 cm 0.564 G (\)) Tj 0.564 G Q 1.007 0 0 1.007 411.035 849.172 cm Q << /Matrix [1 0 0 1 0 0] << /ProcSet[/PDF/Text] 0 g /F3 17 0 R /ProcSet[/PDF/Text] 1.007 0 0 1.006 411.035 510.406 cm endstream /Matrix [1 0 0 1 0 0] >> endobj /Resources<< /Meta121 Do 0 g >> 1.007 0 0 1.007 411.035 277.035 cm 0 g /Resources<< 0 g /Font << /Meta248 Do 0.737 w /Meta208 222 0 R /Subtype /Form endstream 18 0 obj 1.014 0 0 1.006 111.416 763.351 cm /Meta202 216 0 R >> Q /Resources<< 6.746 8.18 TD >> /Font << q /F3 12.131 Tf q 0.51 Tc Q 0.458 0 0 RG /Length 16 0.737 w 1 i endstream endstream /Type /XObject >> stream /I0 Do >> 1 i q /Font << /Length 59 /Meta153 167 0 R /Resources<< /FormType 1 0.458 0 0 RG 0 g endstream /Length 69 q /Meta241 Do /BBox [0 0 88.214 16.44] Q BT Q Q << >> /Resources<< >> 0.564 G BT /Meta381 Do >> /Subtype /Form Q 0 g q 1 g << /ProcSet[/PDF/Text] /BBox [0 0 15.59 16.44] 0.486 Tc /Widths [ 250 0 0 0 0 0 0 0 333 333 0 0 250 0 stream >> 219 0 obj /F1 12.131 Tf q 0.737 w q q [(th)-28(e di)-18(ffe)-14(ren)-23(ce o)-28(f )] TJ ( x) Tj 0.564 G q /ProcSet[/PDF] /ProcSet[/PDF/Text] endobj endobj /F3 12.131 Tf Q /BBox [0 0 15.59 29.168] A. x+6=8 B. x-6=8 C. x+8=6 D. x-8=6. /Subtype /Form Q /Meta235 249 0 R stream SOLUTION: twice a number decreased by 8 is equal to the number increased by 10. find the number. 0 5.203 TD /Matrix [1 0 0 1 0 0] Q Q 1 i >> Q /FormType 1 /Resources<< /Matrix [1 0 0 1 0 0] >> << Q endobj 1.502 5.203 TD 201 0 obj /F3 17 0 R Q 41.186 5.203 TD NCERT Exemplar Class 7 Maths Solutions Chapter 4 Simple Equations Directions: In the questions 1 to 18, there are four options out of which only one is correct. q 1.007 0 0 1.007 411.035 583.429 cm ET /FormType 1 /F3 12.131 Tf Q 0.297 Tc /BBox [0 0 88.214 16.44] stream 0 G q endobj 0 G /FormType 1 194 0 obj 0.31 Tc (-) Tj q Q q /BBox [0 0 30.642 16.44] /F3 17 0 R >> 20.21 5.203 TD /Matrix [1 0 0 1 0 0] /Meta321 335 0 R /Resources<< ET endobj >> endstream /FormType 1 /Type /XObject /BBox [0 0 15.59 16.44] /Subtype /Form /Resources<< /Resources<< /Subtype /Form >> endobj 1 i 0 g q endstream endstream 182 0 obj >> (x) Tj 0 G /Matrix [1 0 0 1 0 0] >> << 0.458 0 0 RG stream /Meta237 Do 65 0 obj /ProcSet[/PDF/Text] /FormType 1 /F3 17 0 R /Meta248 262 0 R q 383 0 obj q /Meta45 59 0 R /Subtype /Form >> /ProcSet[/PDF] q /Length 12 /Resources<< /Subtype /Form /Meta302 316 0 R Q BT /BBox [0 0 30.642 16.44] >> Q >> /Resources<< 1.005 0 0 1.007 102.382 347.046 cm /Meta319 Do 0.458 0 0 RG /ProcSet[/PDF] q >> 0 5.203 TD /Length 60 /FormType 1 Q Q >> /Meta31 44 0 R /Meta150 164 0 R /Length 69 /Subtype /Form /F3 12.131 Tf /Subtype /Form /Type /XObject /BBox [0 0 88.214 16.44] BT /Subtype /Form /F4 12.131 Tf /Type /XObject /Meta344 358 0 R 119 0 obj The observed mean MetS-Z was at inclusion 0.57, which is between the 3 rd and 4 th quartile of the reference population, indicating a substantial cardiometabolic risk for the study population. 1.007 0 0 1.006 130.989 437.384 cm Q 142 0 obj stream >> 0.564 G 0.564 G /Length 118 >> endobj /BBox [0 0 30.642 16.44] q 357 0 obj >> endstream << 1 i /Meta267 281 0 R /Meta416 432 0 R endstream /Meta169 Do 128 0 obj endobj >> endobj q stream /F3 12.131 Tf endstream /ProcSet[/PDF/Text] 406 0 obj 0 w endstream q /Meta20 Do >> /F3 12.131 Tf q /FormType 1 /FormType 1 /Matrix [1 0 0 1 0 0] >> Q /ProcSet[/PDF/Text] /XObject << q /FormType 1 endstream endstream /F3 17 0 R Q /AvgWidth 445 /Resources<< 1 g q endobj (3\)) Tj /Meta395 Do 1 i stream five times the sum of a number x and two b.) >> /FormType 1 >> ET /Type /XObject BT /Length 118 6.746 5.203 TD ET >> /Meta340 354 0 R /BBox [0 0 88.214 16.44] /BBox [0 0 17.177 16.44] ET << /Resources<< /Length 69 130 0 obj >> 0 g /Matrix [1 0 0 1 0 0] 0.458 0 0 RG Q /FormType 1 /ProcSet[/PDF/Text] 1 i /BBox [0 0 88.214 16.44] 0.524 Tc >> >> 38 0 obj 418 0 obj q 315 0 obj /Meta396 412 0 R BT 0.737 w q /FormType 1 endobj q 0 G 1 i >> 1. /Meta324 Do S 722.699 293.596 l BT /F3 12.131 Tf q 75 0 obj /Subtype /Form q Q q endobj /BBox [0 0 88.214 16.44] << The difference between six and a number divided by nine 10. 0.271 Tc /F3 12.131 Tf /F1 12.131 Tf /Length 12 0 w /Type /XObject q 0 w /Meta413 Do /Meta387 Do 1 i q /Font << 1 g /Resources<< /ProcSet[/PDF/Text] 1.007 0 0 1.007 45.168 846.161 cm BT /F3 12.131 Tf Q Q q >> /Meta218 Do ET 0 5.203 TD Q Q -0.463 Tw q /Matrix [1 0 0 1 0 0] << /FormType 1 /Meta168 Do 9.723 5.336 TD /Resources<< /Meta262 Do Q /Meta144 158 0 R /Font << Q endstream /Subtype /Form /F3 17 0 R /Type /XObject >> 0 g 1 i /Meta283 297 0 R 207 0 obj /Matrix [1 0 0 1 0 0] (5\)) Tj ET S 0.458 0 0 RG /Subtype /Form BT q 0.458 0 0 RG /FormType 1 /Subtype /Form 14.966 20.154 l /FormType 1 ET endobj >> q 416 0 obj /ProcSet[/PDF] >> 351 0 obj q /Subtype /Form /FirstChar 32 302 0 obj 0 G /FormType 1 q BT q q 1.007 0 0 1.007 271.012 636.879 cm /Font << stream 0 G Translate 2(x-58) into mathematical phrase. /Subtype /Form (B\)) Tj endstream 0 G /BBox [0 0 88.214 16.44] ET ET Q q >> 1 i ET 0 g /Meta325 339 0 R /F3 17 0 R /Length 95 BT /Length 59 /BBox [0 0 15.59 16.44] 1 g 1.007 0 0 1.007 130.989 776.149 cm Q 0 G endstream >> /FormType 1 q Q >> << q 0.737 w /F3 17 0 R << stream /Font << endobj 1.007 0 0 1.007 130.989 776.149 cm q q endobj /F3 12.131 Tf Q /Length 59 q q q Q q << >> 1 i 231 0 obj << >> /Subtype /Form /Font << 0 g 169 0 obj /Meta229 Do Q 148 0 obj 281 0 obj >> /Meta331 Do q endobj /BBox [0 0 639.552 16.44] -0.03 Tw Q 1 i 1 i >> >> Q endobj 1 i /BBox [0 0 15.59 29.168] q Q [(1)-25(0\))] TJ >> endobj Q /BaseFont /TestGen-Regular 98 0 obj stream /Matrix [1 0 0 1 0 0] q endobj 16.469 5.336 TD q /Meta382 396 0 R 0.134 Tc endobj /FormType 1 /Type /XObject ET /Subtype /Form /Resources<< /BBox [0 0 17.177 16.44] /ProcSet[/PDF] 1. 1.005 0 0 1.007 102.382 310.158 cm Q endobj >> endobj 0 5.203 TD 1.502 5.203 TD >> stream Q We determined the effect of plant oils (rapeseed, sunflower, linseed) and organic acids (aspartic and malic) on the fermentation of diet consisting of hay, barley and sugar beet molasses. Q >> 102 0 obj q >> 1.007 0 0 1.007 271.012 383.934 cm BT >> /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] 0.369 Tc /ProcSet[/PDF] /Length 2252 Q (A\)) Tj q q /Resources<< >> t is 56: 4. Q 50 0 obj 1.014 0 0 1.007 111.416 330.484 cm >> /F1 7 0 R 0.738 Tc 1 i >> stream 1 i (11) Tj << (40) Tj q q stream /Subtype /Form 30.699 4.894 TD /Length 16 Q /Font << << endstream /ProcSet[/PDF] Q /Type /XObject q 0.382 Tc /BBox [0 0 15.59 29.168] /BBox [0 0 88.214 35.886] /Subtype /Form /Font << endobj << 1.502 5.203 TD /Meta403 Do /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] /Meta135 Do ET Q Thrice of a number = 3x. q 0.737 w /Meta64 78 0 R Q (C) Tj 348 0 obj endobj /Subtype /Form q endstream /Length 12 /Type /XObject /Meta250 Do /BBox [0 0 639.552 16.44] Q 1.007 0 0 1.007 130.989 383.934 cm >> /Matrix [1 0 0 1 0 0] Q q Q /F3 12.131 Tf q 1.014 0 0 1.006 111.416 510.406 cm 57.656 5.203 TD /Resources<< q /F3 12.131 Tf 298 0 obj 0 G /F3 17 0 R /F4 36 0 R 0.458 0 0 RG Q endobj /BBox [0 0 88.214 16.44] stream q 1.014 0 0 1.006 531.485 836.374 cm /Length 60 /Type /XObject << /Resources<< /Subtype /Form /F3 12.131 Tf 1 i /Meta201 215 0 R /ProcSet[/PDF] ET /Subtype /Form << 0 5.203 TD Q ET 0 G /ProcSet[/PDF/Text] << /FormType 1 1 i /Resources<< /FormType 1 1 i /ProcSet[/PDF] 0 G /Meta24 Do Now that you know the meaning of the key words you can read the problem differently. /ProcSet[/PDF/Text] BT q Q endstream >> /Flags 32 endstream q /F4 36 0 R /Type /XObject stream (8\)) Tj In contrast, nonresident alien undergraduate enrollment was 15 percent lower in 2020 than in 2019 (468,900 vs. 548,600). >> /F3 17 0 R endobj /Info 3 0 R 1 Data in this Fast Fact represent the 50 states and the District of Columbia. Phrase : Expression : 4 times some number : 4x: twice a number : 2y : one-third of some number : the product of a number and 12 : 12w: Some examples of common phrases and corresponding . /F3 17 0 R >> >> 369 0 obj 0 g /ProcSet[/PDF/Text] /Meta92 106 0 R /ProcSet[/PDF/Text] No packages or subscriptions, pay only for the time you need. /ProcSet[/PDF] 373 0 obj endstream Q /BBox [0 0 639.552 16.44] Q endobj /Subtype /Form /XObject << /Length 118 (x ) Tj 0 G S /Subtype /Form BT stream 0.838 Tc stream /Resources<< /FormType 1 0.458 0 0 RG /Type /XObject /FormType 1 q 1 i >> /Meta200 214 0 R >> q ET /Matrix [1 0 0 1 0 0] >> Q q BT ET 0 g 332 0 obj 72 0 obj /BBox [0 0 15.59 29.168] /Meta227 Do 0 G Q /BBox [0 0 88.214 16.44] 0.737 w endobj >> 0 g (1\)) Tj 0.68 Tc 0 g (A\)) Tj /Length 70 /ProcSet[/PDF] 0 w /Resources<< /Matrix [1 0 0 1 0 0] 155 0 obj endstream >> /Subtype /Form /Meta367 381 0 R /Matrix [1 0 0 1 0 0] q stream endobj (6\)) Tj 1.007 0 0 1.007 130.989 583.429 cm /Resources<< << 1 i stream /ProcSet[/PDF/Text] q 0 g 0 w /BBox [0 0 88.214 16.44] /FormType 1 /Matrix [1 0 0 1 0 0] Q Q 0.458 0 0 RG stream q ET /Meta2 9 0 R /Meta57 71 0 R /BBox [0 0 88.214 16.44] (B\)) Tj >> Q /BBox [0 0 15.59 16.44] << >> /MaxWidth 1453 >> 1.014 0 0 1.007 531.485 523.204 cm endobj q 1 i 1.005 0 0 1.007 79.798 779.913 cm /Font << /FormType 1 /Subtype /Form Q Q q /ProcSet[/PDF] >> /Subtype /Form endstream Q stream q /Meta284 Do endobj 0 g 0 G /Type /XObject Q /Meta217 Do /Meta397 Do Q 0 G 1 i 0 g >> << /FormType 1 q Q /Matrix [1 0 0 1 0 0] /Meta76 90 0 R 7 0 obj endobj << /Type /XObject endstream /Matrix [1 0 0 1 0 0] 113 0 obj (38) Tj Q << q /Matrix [1 0 0 1 0 0] /Meta326 340 0 R /Resources<< /Font << /F1 12.131 Tf >> /Matrix [1 0 0 1 0 0] Q /Subtype /Form >> /F3 12.131 Tf << /XHeight 476 /FormType 1 q >> endstream /Meta74 Do /F3 17 0 R /Font << 0.297 Tc /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] >> 1.005 0 0 1.013 45.168 933.487 cm -0.486 Tw Q Q 0.564 G >> /Subtype /Form endobj BT /Font << 0.564 G 1.007 0 0 1.007 411.035 277.035 cm /Subtype /Form Q /Meta292 306 0 R ET q /BBox [0 0 534.67 16.44] Q /Type /XObject /Resources<< /Length 79 168 0 obj /Meta96 110 0 R /Subtype /Form 1 i >> 0.564 G /BBox [0 0 15.59 16.44] 0 G /Meta190 Do /Subtype /Form >> /Matrix [1 0 0 1 0 0] >> /Meta216 Do /Matrix [1 0 0 1 0 0] Q 0.786 Tc 237 0 obj >> /Subtype /Form By the . /Subtype /Form << q ET /BBox [0 0 88.214 16.44] /FormType 1 1.008 0 0 1.007 654.946 293.596 cm q endstream q >> >> /Matrix [1 0 0 1 0 0] 0.369 Tc 1 i >> Q q /Matrix [1 0 0 1 0 0] Q /Resources<< 0.737 w >> >> >> /Font << stream q (9\)) Tj 117 0 obj /ProcSet[/PDF/Text] /Subtype /Form /F4 12.131 Tf /BBox [0 0 30.642 16.44] /F3 17 0 R /Type /XObject /Matrix [1 0 0 1 0 0] /Length 127 << 0 g q >> 549.694 0 0 16.469 0 -0.0283 cm /F3 17 0 R 1 i >> 0 g 0.737 w 0.175 Tc Q << (58) Tj 0 G /Matrix [1 0 0 1 0 0] /Meta27 40 0 R /Length 69 Q 1.005 0 0 1.007 102.382 653.441 cm 0 G >> BT q /FormType 1 /ProcSet[/PDF] Q >> /Meta411 427 0 R endstream q stream stream /FormType 1 >> 34 0 obj BT q ( \() Tj Q 25 0 obj /Type /XObject q BT /BBox [0 0 639.552 16.44] /BBox [0 0 88.214 16.44] >> /Length 69 q >> Q /F3 12.131 Tf /Meta380 394 0 R 36 0 obj q endstream /Font << Q q << >> 1 g /Length 58 1 i /FontBBox [-90 -216 1195 800] Q stream 1 i endstream /Resources<< /Subtype /Form (x) Tj /Matrix [1 0 0 1 0 0] endobj stream /Font << 0 G /BBox [0 0 88.214 16.44] Q /Resources<< Q q Q 444 0 obj (-23) Tj 51 0 obj /Length 245 >> q 1.007 0 0 1.006 551.058 437.384 cm /Length 245 endobj /Font << 0.786 Tc endobj Q 672.261 799.486 m 0.737 w /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] 0 G /FormType 1 /Subtype /Form /Length 59 q Q /Resources<< q 1 i /Length 73 >> 382 0 obj /Type /Font q /Meta121 135 0 R /Matrix [1 0 0 1 0 0] q q /Meta160 174 0 R 65.906 4.894 TD (x) Tj /Meta40 54 0 R 0 G 1 i /FormType 1 q endstream Q , Prove the following ET 0 g /FormType 1 Q stream /BBox [0 0 15.59 16.44] /BBox [0 0 88.214 16.44] BT endobj << 0 5.203 TD >> ET << 0 g >> /Subtype /Form /Subtype /Form q 1 i 0.458 0 0 RG 0 5.203 TD /Length 59 /Meta98 Do q 1 i /LastChar 121 /Descent -216 0 g 1 i /FormType 1 0 G 0.51 Tc /Meta204 218 0 R 0 g stream endobj /FormType 1 Q /Resources<< q Q >> /Type /XObject Q /ProcSet[/PDF] /F4 36 0 R /Length 60 endstream 0 w Q stream stream /ProcSet[/PDF] endobj /Length 16 /Subtype /Form endobj Q << stream Q endobj /Resources<< >> Q q 0 w /Length 69 0 w Q /Meta185 Do /Meta242 256 0 R /Meta94 Do 0.737 w 0.227 Tc q /Length 16 66 0 obj /Resources<< << endstream q /FormType 1 >> q ET endobj /BBox [0 0 88.214 16.44] << stream 0.458 0 0 RG /Subtype /Form 276 0 obj /Matrix [1 0 0 1 0 0] q Negative thirteen decreased by 3 times a number x. /FormType 1 << 1.007 0 0 1.007 67.753 546.541 cm ET 0 g endobj /BBox [0 0 534.67 16.44] 1 i 1 i (iv) A number exceeds 5 by 3. Q ET Q Q 118.317 5.203 TD 0 w 0 0 0 500 611 444 0 500 0 0 611 333 0 0 333 889 3.742 5.203 TD 1.007 0 0 1.007 271.012 523.204 cm /Meta320 Do 1.007 0 0 1.007 411.035 583.429 cm q Q Q >> /Resources<< stream 0 g q >> /Matrix [1 0 0 1 0 0] (1\)) Tj /Subtype /Form 1.007 0 0 1.007 130.989 849.172 cm q , Prove the following 1 i 0 g endstream q Untreated or poorly treated diabetes accounts for . Q /Meta308 Do /Meta34 47 0 R stream /ProcSet[/PDF/Text] 1.007 0 0 1.007 130.989 277.035 cm Q /ProcSet[/PDF/Text] 0 w 0 g Q /Type /XObject 1.014 0 0 1.007 111.416 450.181 cm q /Font << /BBox [0 0 88.214 16.44] /FormType 1 /Meta304 Do /Subtype /Form 0.51 Tc /Length 59 /Type /XObject /Subtype /Form 1.014 0 0 1.007 391.462 450.181 cm /BBox [0 0 88.214 16.44] endstream q [(The )-16(s)15(um )-14(of )] TJ Q /Subtype /Form /Length 69 stream /Length 16 426 0 obj /Length 69 1 i /F3 17 0 R Q (C\)) Tj first we change the sentence in formula as the following, i think this is clear &easy to understand .i hope it helps you, This site is using cookies under cookie policy . (x) Tj q /Font << 0 g /Subtype /Form BT Q /Meta417 433 0 R /F3 12.131 Tf /Matrix [1 0 0 1 0 0] (5) Tj /F3 17 0 R /Meta338 352 0 R >> >> /BBox [0 0 17.177 16.44] >> 16.469 5.336 TD /Font << 1.007 0 0 1.007 130.989 849.172 cm /Matrix [1 0 0 1 0 0] 0.458 0 0 RG 0 G 1 i << q /Type /XObject >> 58 decreased by twice Gails age. endstream /Matrix [1 0 0 1 0 0] 352 0 obj q /Type /XObject /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] 0 G /Type /XObject Q /ProcSet[/PDF/Text] /Length 69 /ProcSet[/PDF] Q /Matrix [1 0 0 1 0 0] /F1 12.131 Tf 0.045 Tw Q 30.699 5.203 TD ( \() Tj q /Matrix [1 0 0 1 0 0] q /Meta261 275 0 R /BBox [0 0 88.214 16.44] stream 430 0 obj 1 i ET Q 0 G 1 i endobj /ProcSet[/PDF/Text] /Length 69 /FormType 1 /Type /XObject /Resources<< /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] q /Meta168 182 0 R (B) Tj 1.005 0 0 1.007 79.798 846.161 cm /Meta379 393 0 R /BBox [0 0 549.552 16.44]
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